Every redox reaction is a story about who gets the electrons. For decades chemists have worked with a simple rule: if two molecules are competing for an electron, the one that is easier to reduce wins. In August 2026 a team from the University of Wisconsin–Madison, Colorado State University and the University of Colorado Boulder reported in Nature a catalyst that gets around that rule[1]. The idea is surprisingly simple: set the electron free first, and choose the winner afterwards.
Redox in one paragraph
GCSE coreReduction is gain of electrons; oxidation is loss (OIL RIG). A reducing agent gives electrons away; an oxidising agent accepts them. Some substances accept electrons much more readily than others. At A-Level you measure that with standard electrode potentials (E°): the more positive the E°, the more easily a species is reduced. For example, Cu²⁺ (E° = +0.34 V) is reduced far more easily than Zn²⁺ (E° = −0.76 V), which is why zinc metal displaces copper from copper sulfate solution, but copper cannot displace zinc.
The rule, and why it is a problem
A-Level extensionIn organic synthesis, chemists often want to add an electron to a particular molecule to make it react. The trouble comes when a mixture contains two molecules (or two parts of one molecule) that could accept it. Normally the electron goes to whichever is easier to reduce[1]. If the one you actually want to react is the harder one, you are stuck: the electron is always captured by the other.
Switch between the two models. Usually, the electron goes straight to the easier-to-reduce molecule A. With the new catalyst, a free electron in solution can reach either; only B goes on to product, and A gives its electron back. Schematic.
The trick: release the electron first
Over five years, Zachary Wickens's group developed a new family of photoredox catalysts, molecules that use light energy to drive electron transfer[1]. When lit, this catalyst does not hand its electron straight to a neighbouring molecule. Instead it releases it directly into the surrounding solution, creating an extremely reactive free (solvated) electron[1]. As the team put it, “anything is better than the electron freely floating in solution”[1]: the free electron reduces whatever it meets, easy or hard.
The selectivity then comes after the transfer. The molecule you want goes on to react and form product, which removes it from the competition. An unwanted molecule that received the electron has nowhere useful to go, so it passes the electron back and is recycled[1]. Over time, the product builds up from the “harder” molecule even though the “easier” one is present. Computational studies (Robert Paton, Colorado State) and spectroscopy (Niels Damrauer, CU Boulder) helped confirm the mechanism[1].
“This is not just another synthetic method; it's a new way to design redox reactions.” Zachary Wickens[1]
Quick check
Using E° values, which ion is most easily reduced: Zn²⁺ (−0.76 V), Fe²⁺ (−0.44 V) or Ag⁺ (+0.80 V)?
The distinction students often miss
Thermodynamics vs kinetics.
Why it could matter
- Medicines: drug molecules often contain several groups that could be reduced; being able to choose the harder one opens new routes[1].
- Materials: new ways to build and modify polymers and functional molecules[1].
- Light-driven chemistry: another example of using light instead of harsh reagents or high temperatures.
The work is at the laboratory stage, and how widely it applies is still being explored.
Exam-style question
Zinc is added to a solution containing both Cu²⁺ and Fe²⁺ ions. Use E° values (Cu²⁺/Cu +0.34 V; Fe²⁺/Fe −0.44 V; Zn²⁺/Zn −0.76 V) to explain which ion is reduced first and write the ionic equation. [3 marks]
Show model answer and mark breakdown
- Cu²⁺ has the more positive E°, so it is the stronger oxidising agent and is more easily reduced (1 mark)
- so zinc reduces Cu²⁺ first (Fe²⁺ is reduced only once Cu²⁺ is used up, if enough zinc remains) (1 mark)
- Zn + Cu²⁺ → Zn²⁺ + Cu (1 mark)
Examiner focus: compare E° values explicitly and state which species is the stronger oxidising agent.
Common mistake: choosing the ion with the more negative E° as 'more reactive' and therefore reduced first. Negative E° means harder to reduce.
This is a nice example to quote in a redox or electrochemistry answer, and it shows that even well-known rules have clever exceptions. Our chemistry tutoring covers electrode potentials step by step, and our post on how catalysts work explains reaction pathways and activation energy.
Want to revise this topic?
Mostak offers online one-to-one GCSE and A-Level tuition focused on understanding, exam technique and application.
Sources and further reading
- ScienceDaily: Chemists set electrons free and break a decades-old chemistry barrier (Aug 2026) — Nature, 9 Aug 2026: UW–Madison, CSU, CU Boulder; mechanism; quotes
- Nature (2026): the Wickens group paper — research paper
- Wikipedia: Solvated electron — background
Last reviewed: 5 October 2026. Figures are typical published values and rules can change. Exam wording varies by specification, so check yours.
Frequently asked questions
What rule did the chemists break?
When two molecules compete to receive an electron, the electron normally goes to the one that is easier to reduce. That has long limited which reactions chemists can run: a harder-to-reduce molecule cannot react if an easier one is present. A team led by Zachary Wickens at the University of Wisconsin–Madison reported in Nature (August 2026) a way around it.
How does the new catalyst get around it?
It is a photoredox catalyst that, when lit, releases an electron directly into the surrounding solution. That free (solvated) electron is so reactive that it can reduce either molecule. Selection then happens afterwards: the desired molecule continues on to the product, while an unwanted one that grabbed the electron simply hands it back.
What is a solvated electron?
An electron that is not attached to any atom or molecule but is surrounded and stabilised by solvent molecules. Solvated electrons are among the most powerful reducing agents known; they give liquid ammonia containing dissolved sodium its striking blue colour.
Why does this matter?
It opens reactions that were previously out of reach, which could help in making medicines and new materials. The researchers describe it as a new way to design redox reactions, though it is still at the laboratory stage.
Reader ratings & reviews
Rate this article across a few different things — your rating helps other readers, and helps us improve.
Was this article helpful?
Tell us what you think — a correction, a question it left unanswered, or a topic you'd like covered next.
Prefer To Talk? Book a free video call at a time that suits you: 15 minutes for a quick question, 30 for anything else. Times show in your own time zone.

About the author
Sudershan Soni
Founder & Lead Tutor at Mostak Services — an MSc-qualified Mathematics, Science, Computer Science & STEM tutor with 20+ years of professional experience, teaching students from 11+ and GCSE to A-Level and beyond, online worldwide.
Read full profile